How Do Voltage and Magnetic Fields Affect Electron Force?

AI Thread Summary
To determine the speed of an electron accelerated through a voltage, the kinetic energy gained can be calculated using the equation KE = qV, where q is the charge of the electron and V is the voltage. For the given problem, the electron's speed can be derived from its kinetic energy using the formula v = sqrt(2KE/m), where m is the mass of the electron. Similar calculations apply to the positive ion, where its velocity can also be found using the potential difference and its mass. The magnetic force acting on the charged particles can then be calculated using the formula F_b = q(v * B). Understanding these relationships is crucial for solving problems involving charged particles in electric and magnetic fields.
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Homework Statement


An electron is accelerated through 2400V from rest and then enters a region where there is a uniform 1.7 T magnetic field. What are (a) the maximum and (b) the minimum magnitudes of the magnetic force acting on this electron?


Homework Equations


F_{b}=q(v * B)


The Attempt at a Solution


I'm unsure of where to start. How do you calculate the speed (v) if they only give you the voltage that the electron goes through? I have all of the other required information to plug in the equation but not the speed of the electron. Thanks.
 
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Here is another problem in which I cannot find the velocity of the particle:
A singly charged positive ion has a mass of 2.50 x 10^-26 kg. After being accelerated through a potential difference of 250V, the ion enters a magnetic field of 0.500 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field.

How do you find the velocity of the ion given the potential difference it travels through? I know how to solve the rest of the problem but I'm just stuck on the speed (v) of the particle.
 
You can get the velocity of the electron by calculating the kinetic energy it gains in the field. The rest mass of the electron is well known but I can't remember it.

Same for the second question but a different energy and mass involved.
 
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