Simple Harmonic Motion- How Many Times Does the Diaphragm Move Back and Forth?

AI Thread Summary
The discussion revolves around calculating the number of cycles a loudspeaker diaphragm completes in simple harmonic motion over 1.5 seconds, with an angular frequency of 8.50 x 10^4 rad/s. The user initially calculated the period (T) and frequency (f) but made an error in multiplying the frequency by the time to find the total cycles. The correct frequency calculation yields approximately 13528.139 cycles per second, leading to a total of about 20292.209 cycles in 1.5 seconds. The user seeks clarification on the calculation error, emphasizing the importance of accuracy in mathematical operations. The thread highlights common pitfalls in physics calculations and the need for careful verification of results.
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Simple Harmonic Motion-Help Please :)

Homework Statement



A loundspeaker diaphragm is producing a sound for 1.5 s by moving back and forth in a simple harmonic motion. The angular frequency of the motion is 8.50 104 rad/s. How many times does the diaphragm move back and forth?

________ times

Homework Equations



ang.freq.=2pi/T

f=1/T

The Attempt at a Solution



Ok, so I plugged in w=85000rad/s and t=1.5s and got T=0.00007392 and f=13528.139 cycles/sec and

multiplied that f i got by 1.5 sec to get 200292.209 cycles which is wrong..

I don't know what i did wrong...can someone help?
 
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Everything looks right, except f * 1.5s = 20292.209 not 200292.209
 
thanks! i always make dumb mistakes like that haha..
 

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