Net Force on a 1kg ball Rolling on a Banked Track

AI Thread Summary
A 1kg ball rolls on a banked circular track at a 20-degree angle, with a normal force of 10.43N directed inward. To find the net force, the focus is on the radial forces acting on the ball, as the vertical forces balance out. The absence of friction simplifies the calculations, allowing the use of the equation mgtan(20) = (mv^2)/r to determine the speed required for the ball to complete the turn. The derived formula for velocity is v = (rgtan(20))^(1/2), which incorporates the radius of the track and gravitational acceleration. Understanding these dynamics is crucial for solving problems related to motion on banked tracks.
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A 1kg ball rolls along a circular track that is banked at 20 degrees. The normal force on the ball is 10.43N, tilted inward. The radius of the track is 10m.

a. What is the net force on the ball (include direction)?
b. How fast is the ball going for it to complete the turn?

possible equations= radial acceleration=v^2/r, total radial force mv^2/r,

and as for where i am, i don't really know where to start! to find the net force, i know i start with the 10.43N acting on it. I don't know if the 20 degrees comes into play at all or not. any help is greatly appreciated!
 
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What I would recommend you do first is draw a free-body diagram and label all the forces.
 
yeah that was part of the question, i already did that part. i think I've got it right, but where to now?
 
Are you told to ignore friction? Are you given a coefficient of friction?
 
There is no friction, it is being ignored.
 
Okay, when I set up my free body diagram and chose my coordinate system, I got

x: F= -F[N]sin(20)=(-mv^2)/r

y: F= F[N]cos(20) - mg = 0


So, there is no net force in the y direction, it is all in the x direction.


mgtan(20)=(mv^2)/r

v=(rgtan(20))^(1/2)
 

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