Finding mass per unit length for stretched strng given tension?

AI Thread Summary
The discussion focuses on calculating the mass per unit length of a stretched string given a tension of 5N and a wave equation. Key parameters identified include an amplitude of 0.1 m, a wavelength of 0.4 m, and an angular frequency of 4 rad/s, leading to a wave velocity of 0.1 m/s. The relationship between wave speed, tension, and density is highlighted, with the formula v = √(T/ρ) being crucial for determining mass per unit length. The user successfully solved the problem using this relationship and provided insights on sketching the wave's variation with position. The thread concludes with a solution that emphasizes the connection between wave properties and physical parameters of the string.
coffeem
Messages
91
Reaction score
0
[SOLVED] Finding mass per unit length for stretched strng given tension?

A transverse wave on a stretched string under Tension = 5N is defined by the equation:

y(x,t) = 0.1cos(2pi/5(x - 10t)

Find:

a) amplitude = 0.1 m

b) wavelength = 0.4 m

c) angular frequency = 4 rad/s

d) wave velocity = 0.1. m/s

e) mass per unit length ?

f) for t = 0, sketch how y varies with x. ?


I can do the first 4 parts be using the solution to the wave equation. Any ideas on how to do the other two bits? thanks.
 
Physics news on Phys.org
Hey thanks for anyone for looking at this. However I have been able to solve it another way. If anyone is interested the answer is:

wave speed v relates tension and density:

v = root(T/rho)

and you can set t=0 in that equation and you have something like y=acos(kx)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top