How Do You Rearrange the Speed of Sound Equation to Solve for M in Gas?

AI Thread Summary
To rearrange the speed of sound equation for gas, start with v = sqrt[(gamma * R * T) / M]. Squaring both sides gives v² = (gamma * R * T) / M. Next, multiply both sides by M to get M * v² = gamma * R * T. Finally, divide both sides by v² to isolate M, resulting in M = (gamma * R * T) / v². This corrects the initial attempt and provides the proper formula for M.
cseet
Messages
40
Reaction score
0
Hi all,

can you pls show me how you rearrange the speed of sound in gas equation from the original equation of:

v (sound) = sqr of [(gamma * R * T) / M]

I would like to find M, I tried to rearrange it to the following:

M = sq of [(gamma * R * T) / v]

pls kindly correct me with these.

thanks
cseet
 
Physics news on Phys.org
cseet said:
Hi all,

can you pls show me how you rearrange the speed of sound in gas equation from the original equation of:

v (sound) = sqr of [(gamma * R * T) / M]

I would like to find M, I tried to rearrange it to the following:

square both sides (in algebra you try to treat each side the same way)

v2 = (gamma * R * T) / M

multiply each side by M (doing the same thing to RHS and LHS is fair)

M * v2 = (gamma * R * T)

divide both sides by v2

M = (gamma * R * T)/ v2
 
thanks marcus

thanks Marcus, you're a gem!
cseet
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top