Adiabatic steady state flow in a nozzle

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SUMMARY

The discussion centers on the calculation of exit temperature in an adiabatic nozzle flow, where air enters at 300 kPa, 200°C, and 30 m/s, and exits at 100 kPa and 180 m/s. The energy balance equation yields an exit temperature of 184°C, while the pressure-temperature relation using k = 1.4 produces different results. The discrepancy arises because the pressure-temperature relation is valid only for isentropic flows, whereas the energy balance equation applies to inviscid adiabatic flows. Thus, the two equations will only yield consistent results under isentropic conditions.

PREREQUISITES
  • Understanding of adiabatic processes in thermodynamics
  • Familiarity with the energy balance equation for fluid flow
  • Knowledge of isentropic flow and its conditions
  • Basic principles of ideal gas behavior and specific heat capacities
NEXT STEPS
  • Study the derivation and application of the energy balance equation in fluid dynamics
  • Learn about isentropic processes and their significance in thermodynamic systems
  • Explore the implications of specific heat variations in real gas flows
  • Investigate the conditions under which the pressure-temperature relation is applicable
USEFUL FOR

Mechanical engineers, thermodynamics students, and professionals involved in fluid dynamics and nozzle design will benefit from this discussion.

jason.bourne
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air enters an adaibatic nozzle steadily at 300 kPa, 200 degree celsius and 30m/s and leaves at 100 kPa and 180 m/s.
find the exit temperature?

when m using energy balance equation: h1 + [ (v1)^2 / 2 ] = h2 + [(v2)^2 / 2 ]
i get the answer 184 degree celsius.

but when i use the other relation i.e, pressure temperature relation

[ T1 / T2 ] = [ P1 / p2 ]^ ((k-1)/k) (i used k = 1.4)

i get very different values of temperature. is this equation not valid?
why m i getting different answers?

is this pressure temperature relation only valid for reversible processes?
 
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The first equation (with h1 and h2 in it) works for inviscid adiabatic flows (with no work done on the fluid by propellers, etc). It does not require flow to be reversible. As a result, it will work even across the shock wave.
The second equation works only for isentropic flows - i.e. reversible, adiabaric flows.

Thus, these two equations will yield the same answers (assuming p1, p2, h1, h2 , T1 are somehow known or given) only for isentropic flows.
 
jason.bourne said:
air enters an adaibatic nozzle steadily at 300 kPa, 200 degree celsius and 30m/s and leaves at 100 kPa and 180 m/s.
find the exit temperature?

when m using energy balance equation: h1 + [ (v1)^2 / 2 ] = h2 + [(v2)^2 / 2 ]
i get the answer 184 degree celsius.

but when i use the other relation i.e, pressure temperature relation

[ T1 / T2 ] = [ P1 / p2 ]^ ((k-1)/k) (i used k = 1.4)

i get very different values of temperature. is this equation not valid?
why m i getting different answers?

is this pressure temperature relation only valid for reversible processes?

The first equation is the based on the full energy balance (with some assumptions that drop out some terms). It always works.

The second is for an Ideal gas, isentropic, and constant specific heat assumption.

Based on your problem description, the system does not meet the criteria for the second relation. If your system was given as isentropic, ideal gas, with constant specific heats, then you could use the second relation you listed.

BTW you have the T1/T2 and P1/P2 inverted (T2 and P2 are the numerators).

CS
 
thank you so much
 

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