Is There an Easier Way to Solve this Definite Integral?

simo
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Homework Statement



solve the integral: ∫_(-∞)^∞▒〖x^2 e^(-λ(x-a)^2 ) 〗 dx
where λ and a are positive real constants


The Attempt at a Solution



I tried integration by parts with and without y-substitution but neither worked for me.

Without substitution, I set up the integral to look like:
∫_(-∞)^∞▒〖xe^(-λx^2 )•xe^λa(2x-a) 〗 dx

u=xe^λa(2x-a) and dv=xe^(-λx^2 ) dx

after doing this a few times I realized it wouldn't work.

For y-substitution I used y = x-a. ∫_(-∞)^∞▒〖(y+a)^2 e^(-λ(y)^2 ) 〗
I then tried to integrate this by parts with u=(y+a)^2 and dv=e^(-λy^2 )
 
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I assume you want to solve
\int_{-\infty}^{\infty} x^2 e^{-\lambda (x - a)^2 } \, dx

In that case, try differentiation of an ordinary Gaussian integral w.r.t \lambda (twice).
 
Yea, I didn't have it in the right form. It's for a physics class, so the books says to use a table to help. I think I will try to solve it out anyway. Thanks for the help.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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