Analyzing an Elastic Collision Between Two Hockey Pucks

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Homework Help Overview

The problem involves an elastic collision between two hockey pucks, where one puck is initially moving and the other is at rest. The first puck is deflected at an angle after the collision, and the task is to determine the speed and direction of the second puck post-collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of momentum and kinetic energy in elastic collisions, with some emphasizing the need to analyze velocity components separately. Questions about vector representation and the setup of equations are raised.

Discussion Status

Some participants have provided guidance on setting up the equations for momentum and kinetic energy, while others express uncertainty about the physics concepts involved. There is an indication that one participant has reached a resolution independently.

Contextual Notes

Participants note the importance of understanding vector components in the context of the problem, and there is a mention of the original poster's lack of initial understanding.

nsaZn23
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Homework Statement


A hockey puck moving at 0.43 m/s collides elastically with another puck that was at rest. The pucks have equal mass. The first puck is deflected 35° to the right and moves off at 0.36 m/s. Find the speed and direction of the second puck after the collision.


Homework Equations


1/2mv2 + 1/2mv2 = 1/2mv2 + 1/2mv2
momentum initial = momentum final


The Attempt at a Solution


no idea
 
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Start by putting the equations for initial momentum and final momentum.

[tex]m \vec{v_{1}} + m \vec{0} = m \vec{v_{1}}' + m \vec{v_{2}}'[/tex]

then set up the KE equations too
 
nsaZn23 said:

Homework Statement


A hockey puck moving at 0.43 m/s collides elastically with another puck that was at rest. The pucks have equal mass. The first puck is deflected 35° to the right and moves off at 0.36 m/s. Find the speed and direction of the second puck after the collision.


Homework Equations


1/2mv2 + 1/2mv2 = 1/2mv2 + 1/2mv2
momentum initial = momentum final


The Attempt at a Solution


no idea

This would be an elastic collision.
http://en.wikipedia.org/wiki/Elastic_collision#One-dimensional_Newtonian

You would want to focus on the conservation of momentum, not the conservation of energy.

In this regard you need to identify the components of the x,y velocity and add them separately to determine the components of the one you don't know. Then recombine the components to give the right answer.
 
uhhh I'm bad at physics can you elaborate?
 
nsaZn23,

are you familiar with vectors?

the problem basically is

[tex]v_{1} \vec{i} + \vec{0} = v_{1}_{x}' \vec{i} + v_{1}_{y}' \vec{j} + v_{2}_{x}' \vec{i} + v_{2}_{y}' \vec{j}[/tex]
 
Yeah,

I see that Mass X Velocity initial1 + Mass X Velocity initial2 = Mass X Velocity Final1 + Mass X Velocity Final2.

nevermind, i figured out how to do the problem, thanks.
 

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