Calculating effective nuclear charge

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SUMMARY

The effective nuclear charge (Zeff) for beryllium (Be) can be calculated using the formula Zeff = Z - S, where Z is the atomic number and S is the shielding constant. In this case, Z is 4 and S is assumed to be 2, leading to an initial calculation of Zeff = 2. However, the discussion emphasizes the importance of incorporating ionization energy into the calculation, specifically using the equation E = RH(Zeff²/n²). The ionization energy provided is 899.4 kJ/mol, which, when substituted into the equation, leads to a derived value of Z²eff = 4.129 x 10²³ mol-1.

PREREQUISITES
  • Understanding of effective nuclear charge (Zeff)
  • Familiarity with the concept of ionization energy
  • Knowledge of the Rydberg constant (RH)
  • Basic principles of quantum mechanics and atomic structure
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  • Learn how to apply ionization energy in atomic calculations
  • Explore the implications of shielding constants in multi-electron atoms
  • Investigate the relationship between energy levels and effective nuclear charge
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Homework Statement



If ionization energy is 899.4 kJ/mol for Be, what is the effective nuclear charge?

Homework Equations


Zeff = Z - S

E=RH(Z2/n2) ??
E=RH(Zeff2/n2)??

The Attempt at a Solution



My attempted solution was subbing into
Zeff = Z - S
Zeff = 4 - 2
= 2

But I suspect that is wrong... because why ionization energy is given.. so shouldn't it be used in the calculation?

And somewhere I think I read that "S" was supposed to be a "constant" of some sort, and I just subbed 2 in because I thought that it was the number of electrons in the first orbital ?
 
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One of the equations you listed contains both ionization energy and effective nuclear charge, why don't you use it?
 
Ah..
So subbing in values
E=899.4 kJ/mol
RH=2.178 x 10-21 kJ
n=1

I get Z2eff= 4.129 x 10 23 mol

How does one get to the units/value of Z2eff after this?
 
Ionization energy was per mole, not per molecule.
 
Oops, just noticed that "Z2eff= 4.129 x 10 23 mol " should actually read "Z2eff= 4.129 x 10 23 mol-1 "

I think that the italicized part is what confuses me the most -- what are the units for this portion? I'm going to take a guess that it is currently molecules/mol, but if so, is this always the case whenever expressing a value and the unit mol-1?

Like for this example, what was given was in kJ/mol. When the kJs were cancelled, what resulted was just mol-1...
 

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