What Do These Symbols and Scopes Mean in Mathematical Notation?

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The double line absolute value is called the norm of a vector. Depending on the field, you might have different definitions. See http://en.wikipedia.org/wiki/Norm_(mathematics )

The second symbol, the brackets, are used to denote the span of two vectors. That is the set of all possible linear combinations of two vectors
 
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found it
i will try to comprehend this stuff
 
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Caution: <a, b> is also often used to mean the inner product of two vectors. In fact, since you refer to it in connection with ||v||, I would be inclined to suspect that is what is meant: ||v||2= <v, v>.

The inner product on a vector space, V, is a function from V\times V to the underlying field, such that
1) &lt;v,v&gt;\ge 0\/itex] and &amp;lt;v,v&amp;gt;= 0 if and only if v= 0.<br /> 2) &amp;lt;au+ bv,w&amp;gt;= a&amp;lt;u,w&amp;gt;+ b&amp;lt;v,w&amp;gt;.<br /> 3) &amp;lt;u,v&amp;gt;= \overline{&amp;lt;v,u&amp;gt;}}.<br /> (that overline is complex conjugate)<br /> <br /> If you are given a basis,{e_1, e_2, \cdot\cdot\cdot, \e_n} for the vector space, so that two vectors, u and v, can be written v= a_12_1+ a_2e_2+\cdot\cdot\cdot+ a_ne_n and u= b_1e_1+ b_2e_2+ \cdot\cdot\cdot+ b_ne_n then the dot product, u\cdot v= a_1b_1+ a_2b_2+ \cdot\cdot\cdot+ a_nb_n is <b>an</b> inner product.
 
so if i have vector a=(x,y,z) b=(s,t,d)

||a||=(x^2 + y^2 +z^2)^0.5

<a,b>=x*s + y*t + z*d

(<a,a>)^0.5 =||a||

is it correct?
 
Yes.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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