What is the de Broglie wavelength of this electron?

AI Thread Summary
To find the de Broglie wavelength of an electron with a kinetic energy of 500 eV, the energy must first be converted to joules, resulting in 8.01x10^-17 J. The de Broglie wavelength is calculated using the formula λ = h/p, where h is Planck's constant and p is momentum. Momentum can be derived from kinetic energy using the equation T = p^2/(2m), where T is the kinetic energy and m is the mass of the electron. The discussion focuses on converting energy to momentum to ultimately determine the wavelength.
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Homework Statement


What is the de Broglie wavelength of this electron?
Given is 500 eV


Homework Equations


KE= 1/2 mv^2
1 eV=1.602x19^-19 J


The Attempt at a Solution


I converted the 500 eV to 8.01x10^-17 via the given conversion. Now I'm stuck.
 
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The deBroglie wavelength is given by the relation

\lambda = \frac{h}{p}

where h is the plank constant and p is momentum. I'm assuming the number in eV you were given is the kinetic energy of the electron--you can look up its mass to get it in terms of momentum through

T \text{(kinetic energy)}=\frac{p^2}{2m}

Can you figure how to get the wavelength of it from this?
 

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