Determine magnetic flux and current

AI Thread Summary
The discussion revolves around a physics homework problem involving two identical circular wire loops, where one loop has a constant current due to a battery and the other does not. Participants are asked to determine if there is magnetic flux through the second loop and whether it generates a current. Additionally, the impact of cutting the wire in the first loop, which stops the current, on the second loop is explored. The importance of providing explanations for each answer and including directions of currents and magnetic fields is emphasized. The thread encourages collaboration and problem-solving among participants.
mar7pau
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Hi mar7pau,

mar7pau said:

Homework Statement


The picture shows too identical circular wire loops with their areas facing each other. The loop on the left has a battery in it as shown, so there is a steady constant current flowing through it. The loop on the right has no battery in it. Answer the following questions (remember, give an explanation for each answer, add directions of currents and magnetic fields to the drawing as necessary):

a.Is there a magnetic flux through the loop on the right?
b.Is there a current in the loop on the right?
c.Supposing I cut the wire of the left loop so current does not flow through it
What happens in the right loop? Why?



Homework Equations


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The Attempt at a Solution


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Please attempt the problem and post both your answers and reasoning; then we'll know how we can help.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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