Hydrogen -Energy State Transitions

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The discussion focuses on finding the algebraic relationship between the wavelengths of transitions in hydrogen-like ions and hydrogen itself, using the formula hν(n1, n2) = C1Z1^2(1/n2^2 - 1/n1^2). Participants clarify that substituting Z=1 simplifies the case for hydrogen, but there is confusion about the question's intent. The relationship can be expressed as λ = 1/Z^2 * (λ for H), highlighting that the only difference between the two cases is the Z^2 factor. Participants emphasize the importance of correctly applying the formulas for frequency and wavelength. The conversation ultimately aims to clarify the algebraic manipulation needed to derive the relationship.
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Homework Statement



Find the (algebraic) relationship between the wavelengths of the equivalent transitions (i.e. same n1 and n2) for hydrogen-like ions of atomic number Z and hydrogen itself.

Homework Equations



I know:

h\nu (n_{1} , n_{2} ) = C_{1}Z_{1}^2(\frac{1}{n_{2}^2} - \frac{1}{n_{1}^2})

And

\nu = \frac{c}{\lambda}



The Attempt at a Solution



But that's as far as I can get really. I know putting Z as 1 will give me the simplest case for Hydrogen, but I'm still a bit perplexed at what the question actually wants. I could rearrange for \lambda, but I'm still unsure if that's on the right lines?

Thanks.
 
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Use lambda = h/v = h^2/(hv) = h^2/(C*Z^2*X)
where X is the big pair of brackets with the transition numbers in it.
You want to compare this with the same expression for hydrogen which is h^2/(C*1*X) unless the C is different for hydrogen, too.
They are the same except for the Z^2 so you'll end up with
lambda = 1/Z^2 * (lambda for H)
 
Sorry, I just realized I've written rubbish:

\nu = \frac{c}{\lambda} Is what is meant to be there!

Sorry
 
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