Designin (very simple) oscillator circuit

In summary: First, you'll want to find the gate-source voltage, Vo:Vo = (Zin - Zin'*Rg) / (Cv + 1)Next, you'll need to find the current through the transistor, I:I = Vo*RgFinally, you'll want to solve for the resonant frequency, f:f = (I*Rg*Cv) / (2*Rs*C2)
  • #1
dalarev
99
0
I'm using the Microwave Office simulating software to design a practice clapp oscillator (picture attached).

I'm at the beginning stages of this project. I will have to design a biasing network for this circuit but, before that, I need to find the formula to find the resonant frequency for this general schematic.

My question is, using an NMOS, should I replace the circuit by its small circuit equivalent circuit? That would help me by ignoring the sources (since it only has DC sources). Also, would I have to consider the internal capacitances of the NMOS?
 

Attachments

  • Clapp_oscillator.png
    Clapp_oscillator.png
    768 bytes · Views: 546
Engineering news on Phys.org
  • #2
dalarev said:
I'm at the beginning stages of this project. I will have to design a biasing network for this circuit but, before that, I need to find the formula to find the resonant frequency for this general schematic.

Here is the formula, it's not hard to derive:

http://en.wikipedia.org/wiki/Clapp_oscillator
My question is, using an NMOS, should I replace the circuit by its small circuit equivalent circuit?

yes, and choose the transistor model you want to use.

That would help me by ignoring the sources (since it only has DC sources). Also, would I have to consider the internal capacitances of the NMOS?

yes, you can design it by knowing the s-parameters or h-parameters if you are working at lower frequencies.

What frequency?
 
  • #3
When you get to the DC biassing, have a look at the attached picture.

The source resistor is a critical component in this because it is directly across one of the capacitors in the feedback network. You also have to take your output from across this resistor. Its value depends on the FET.
Some versions of this circuit show a RFC (Radio Frequency Choke) in series with the source resistor. This is an untuned inductor of about 1 mH.

This circuit is notoriously difficult to get going and it has various other names that are similar to its proper name. None of them are complimentary.

Especially, the two series capacitors need to be chosen so that they have less reactance than the tuning capacitor for stability, but not too much less or the oscillator will not oscillate.

If you do get it going, it is quite a stable oscillator.
 

Attachments

  • Clapp Oscillator.PNG
    Clapp Oscillator.PNG
    1.2 KB · Views: 568
  • #4
waht said:
Here is the formula, it's not hard to derive:

http://en.wikipedia.org/wiki/Clapp_oscillator
Actually, I was told explicitly to ignore that incorrect formula by my professor. Or maybe he just wanted me to derive it myself, which I agree with.


yes, and choose the transistor model you want to use.
I'm going with a common drain NMOS, just because I'm more comfortable with that (as opposed to BJT).

yes, you can design it by knowing the s-parameters or h-parameters if you are working at lower frequencies.

What frequency?
I'm confused by the first sentence. Didn't think that had anything to do with this project.

I am working at ~2.43 Ghz.



vk6kro,
I will put your suggestions to the test when I am at the lab later on today, thanks a bunch for the material.

I am a bit concerned, though, that I am practically lost when it comes to DC biasing networks. Am I correct in assuming this schematic will only have DC sources, and no AC (small) signal generators? I am still a bit confused about that part.

Thanks all for your help.
 
  • #5
This circuit is an oscillator. That means it generates AC but has to be supplied with DC power.
The output would be taken via a series capacitor from the top end of the source resistor

This circuit would not normally be used at 2.43 GHz, but it may work in a simulator.

It would normally be used between 3 MHz and 12 MHz, roughly. It would certainly need the DC conditions to be right before it oscillated.

For oscillation at about 6.5 MHz, values like 10 uH for the coil, 100 pF for the tunable capacitor and 300 pF for the series capacitors might get you somewhere near oscillation. Then you can adjust the variable capacitor to see what sort of frequency output you can get.
 
  • #6
vk, I have subtly changed schematics but still followed your advice for the DC biasing. I am now trying to find the resonant frequency by drawing this (dynamic) equivalent circuit. I have attached a picture though, in case you're interested in seeing what I'm seeing.
 

Attachments

  • clappDC.PNG
    clappDC.PNG
    4.1 KB · Views: 462
  • #7
This may be bordering on the Homework subforum, but I need a bit of guidance in deriving a formula to find the resonant frequency.

I have used the T-model for the NMOS and found that the out impedance, according to my schematic up there,

Zout = Rs / (s*Rs*C2 + 1)

Zin, excluding the transversal capacitor C1 (joined between Gate and Source) :

Zin' = (s^2*Rg*L*Cv + 1) / (s^2*L*Cv + s*Rg*Cv + 1)Any quick suggestions on what might give me some insight?
 
  • #8
The resonant frequency is that of the inductor with 3 capacitors in series across it. You know the formula for capacitors in series.

There is a standard formula for working out resonance.
It is F = 1 / (2 * pi * Square root of { L * C } )

A convenient form of it for RF is as follows:

F = Square root of {25330.3 / (L * C)}

where F is in MHz... C is in pF ...and L is in uH

eg if C =60 pF L = 10 uH then F = 6.5 MHz

If you use an enhancement mode Mosfet you will need to forward bias it by about 2 volts relative to the source.
 
  • #9
Clap oscillator will work fine at a few MHz, but at 2.4 GHz, transmission lines and resonators are used. Transistors are modeled as two-port networks with s-parameters, need to do impedance matching, get Rollets' stability factor for starters etc
 

1. What is an oscillator circuit?

An oscillator circuit is an electronic circuit that produces a periodic, repetitive waveform without needing an external input signal. It is commonly used in electronic devices to generate a stable clock signal or to produce a specific frequency for transmission or detection purposes.

2. How does an oscillator circuit work?

An oscillator circuit consists of an energy source, an amplifier, and a feedback loop. The energy source provides power to the amplifier, which amplifies the signal and sends it back to the input through the feedback loop. This creates an oscillating or repeating pattern of the signal, which is then output by the circuit.

3. What are the components of a simple oscillator circuit?

A simple oscillator circuit typically consists of a resistor, a capacitor, and an inductor connected in a series or parallel configuration. These components, along with an amplifier and feedback loop, work together to generate the oscillating signal.

4. What are the different types of oscillator circuits?

There are various types of oscillator circuits, including RC oscillators, LC oscillators, crystal oscillators, and relaxation oscillators. Each type has its own unique design and characteristics, making them suitable for different applications.

5. What are some common uses for oscillator circuits?

Oscillator circuits are commonly used in electronic devices such as radios, televisions, computers, and cell phones to generate a stable clock signal. They are also used in communication systems, such as radio transmitters and receivers, to produce specific frequencies for transmission and detection.

Similar threads

  • Electrical Engineering
Replies
27
Views
1K
Replies
5
Views
795
  • Electrical Engineering
Replies
3
Views
1K
Replies
9
Views
4K
  • Electrical Engineering
Replies
12
Views
1K
  • Electrical Engineering
Replies
22
Views
2K
Replies
7
Views
1K
  • Electrical Engineering
Replies
3
Views
801
Replies
19
Views
3K
  • Electrical Engineering
Replies
14
Views
4K
Back
Top