Finding the absolute maximum and absolute minimum

meeklobraca
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Homework Statement



Find the absolute max and min of

f(t)=t + cot(t/2) on [pi/4, 7pi/4]

Homework Equations





The Attempt at a Solution



I have attempted to find the derivative which I believe is

1 - csc^2 (t/2) * (t/2) which I can simplify down to cot^2 (t/2) * (t/2)

Even if that is correct, which I am doubtful of, where do I go from here?

Thank You!
 
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Why do you think the derivative of t-cot(t/2) is 1-(csc^(t/2))*(t/2)? Better fix that before you try to proceed.
 
Okay I've found the derivative of t + cot (t/2) to be

1 - csc^2(t/2) * 1/2
 
meeklobraca said:
Okay I've found the derivative of t + cot (t/2) to be

1 - csc^2(t/2) * 1/2

That's much better. So do you have any critical points on [pi/4, 7pi/4]?
 
Here in lies the problem Dick. Where do you go from here?

im at sqrt 2 = csc (t/2) from which I've turned into sqrt 2 = 1/sin (t/2)
 
That's pretty good progress. Actually possibilities are at sin(t/2)=+/-1/sqrt(2). Can you draw a graph of sin(x) and tell me where sin(x)=+/-1/sqrt(2)? Then put t/2=x. I happen to know sin(pi/4)=1/sqrt(2).
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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