Show that he object moves on an elliptical path

  • Thread starter Thread starter Saladsamurai
  • Start date Start date
  • Tags Tags
    Path
Saladsamurai
Messages
3,009
Reaction score
7
Okay then :smile:

Homework Statement



An object moves in the xy-plane such that its position vector is

\bold{r} = \bold{i}a\cos(\omega t)+\bold{j}b\sin(\omega t) \qquad (1)

where a,b, and \omega are constants.

Show that the object moves on the elliptical path

(\frac{x}{a})^2+(\frac{y}{b})^2 =1 \qquad (2)


I have never studied ellipses, so I am 'googling' them now as we speak. I can see that (2) resembles the equation of a circle except that it includes a couple of scaling factors 'a' and 'b'.

I am just not sure how to relate (1) and (2) to each other.

Can I get a friendly 'nudge' here?

Thanks!

~Casey
 
Physics news on Phys.org
\bold{r} = \bold{i}a\cos(\omega t)+\bold{j}b\sin(\omega t) = \bold{i}x +\bold{j}y

Right?

So x = a\cos(\omega t), y = b\sin(\omega t)

Just plug it into the equation (2) in order for it to hold it must hold for all t.
 
Feldoh said:
\bold{r} = \bold{i}a\cos(\omega t)+\bold{j}b\sin(\omega t) = \bold{i}x +\bold{j}y

Right?

So x = a\cos(\omega t), y = b\sin(\omega t)

Just plug it into the equation (2) in order for it to hold it must hold for all t.

Right. I thought I was making it more difficult than it is. I don't know why I thought that there was something more to it. Thanks again! :smile:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top