Stress Strain Diagram: Find Constants E, K, n, and α

Click For Summary

Discussion Overview

The discussion revolves around determining the constants E, K, n, and α from a stress-strain diagram. Participants explore the relationships between stress and different types of strain, including elastic and plastic deformation, while grappling with the implications of the graph's characteristics.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the elastic modulus E from the linear portion of the stress-strain graph, obtaining E=33.33 MPa.
  • Participants discuss the calculation of the constant K for the plastic deformation stage, noting that different points yield different values, leading to confusion about the correct approach.
  • There is a question regarding the absence of a maximum point in the graph, which is typically expected before the necking portion.
  • Another participant raises concerns about the relationship between plastic strain (δ) and elastic strain (ε), suggesting a potential connection involving a constant c representing permanent deformation.
  • Participants express difficulty in solving for K and α, indicating that their calculations yield inconsistent results based on the data points used.
  • There is a recognition that the stress function must equal zero when the strain is zero, complicating the direct substitution of δ for ε after plastic deformation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the values of the constants or the correct relationships between the strains. Multiple competing views and uncertainties remain regarding the calculations and the interpretation of the stress-strain graph.

Contextual Notes

Participants note limitations in their understanding of the relationship between δ and ε, as well as the implications of the graph's features on their calculations. There are unresolved mathematical steps and dependencies on the definitions of the variables involved.

Dell
Messages
555
Reaction score
0
given the following points of the stress strain graph
points.JPG

and knowing that the stages are defined

linear σ=Eε
uniform plastic σ=Kδ2
necking σ=αδ

where ε is an elastic strain and δ plastic strain

find the values of the constants E K n α

using the given data i plotted σ(ε) and got the following
Capture.JPG


now to find the constant E, i take the linear portion and find its incline, i get
E=33.33MPa

as for the others
for the platic deformation, can i take an of the points after (3,9) ?
for each point i chose i get a different value
K=σ/δ2
K=4e4/(13e-4)2=2.366864e10
K=4.5e4/(20e-4)2=1.125e10

is the necking portion not meant to be after a maximum point in the graph? in this graph i have no such point.
 
Physics news on Phys.org
Linear, curved, linear.
 
okay i see what you are saying, so then i can find the curve of the last part as i did for the first part, but how about the curved portion?
 
as i said for each point i take i get a different value
K=σ/δ^2
K=4e4/(13e-4)^2=2.366864e10
K=4.5e4/(20e-4)^2=1.125e10
 
i think that the problem is the relationship between δ and ε, since the graph i have and the data given is for is σ(ε), but the constants i need are for σ(δ) what is the connection between δ and ε?
i thought that δ=ε+c (c being the permanent deformation after the linear portion of the graph,) but i solved the equations using δ=ε+c

σ=αδ
σ=Kδ^2
using the given data

but i cannot solve for K, α, every time i plug in different data i get different values,

i have been using the 1st 3 sets of data for the 1st linear section
the second 3 sets for the parabolic section
the last 2 sets for the final linear section

clearly the δ cannot be raplaced directly by ε since when the stress=0 the function MUST also be 0, and the strain will not be 0 after plastic deformation, looking at the graph we can also see that the parabolic and linear sections will not reach (0,0)
i can find the functions for these curves as a function of the strain ε but not δ which i need in order to find the constants
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
3
Views
3K
Replies
1
Views
3K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
88K