How to find composition using Specific HEat

AI Thread Summary
To determine the composition of a mixture with a specific heat of 780, composed of copper (400) and iron (890), one must establish a model relating specific heat to composition. This involves setting up an equation that accounts for the specific heats of the pure materials and the desired specific heat of the mixture. The problem is classified as an inverse problem, requiring assumptions about the relationship between composition and specific heat. Ultimately, the solution necessitates independent problem-solving, as guidance may not be readily available. Understanding the underlying principles of specific heat and composition is crucial for resolving such inverse problems.
noobatphysics
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IS it possible?
say if the specific heat is 800
and the composition is made up of 2 materials
one which has specific heat of 850
and the other of 750
 
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Its an inverse problem.

You'd need to assume a model for the specific heat as a function of composition and the specific heats of the pure materials, and use the model equation to solve for the unknown compositions.
 
hmmm

say if it was made out of copper n iron
copper having 400 specific heat heat capacity
Iron having 890 specific heat
and the mixture had 780 specific heat capacity
^ assume the values are that
can u show me how to do the inverse problem to find the composition?
 
no one is going to show you how to do anything.

you need to figure it out on your own.
 
Thread 'Thermo Hydrodynamic Effect'

Thread 'Thermo Hydrodynamic Effect'

Vídeo: The footage was filmed in real time. The rotor takes advantage of the thermal agitation of the water. The agitation is uniform, so the resultant is zero. When the aluminum cylinders containing frozen water are immersed in the water, about 30% of their surface is in contact with the water, and the rest is thermally insulated by styrofoam. This creates an imbalance in the agitation: the cold side of the water "shrinks," so that the hot side pushes the cylinders toward the cold...
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