Finding the current on each resistor

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The discussion focuses on solving a circuit problem to find the current through resistors R1, R2, and R3 using Kirchhoff's laws. The initial attempt at applying Kirchhoff's law resulted in incorrect values for the currents, prompting a reevaluation of the equations used. It was clarified that only two independent loop equations can be derived from the circuit, necessitating the use of a junction equation for a complete solution. After adjusting the equations and incorporating the junction relationship, the correct current values were successfully calculated. The conversation also included a side note about using forum tags for formatting replies.
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Homework Statement


[PLAIN]http://img297.imageshack.us/img297/7053/96217079.jpg

given this circuit find the current on R1,R2 and R2

Homework Equations


I = V/R

The Attempt at a Solution



i applied kirchhof's law and I have this:

36 - 5*I - I1*4 = 0
36 - 5*I + 20 - 2*I2 - 14 = 0
20 - 2*I2 - 14 + I1*4 = 0

and i find I1 = 66/19 which is wrong
the book says
I1 = 1.10 A
I2 = 5.21 A
I = 6.32 A

what am i doing wrong?
 
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Hi kliker! :smile:

(try using the X2 tag just above the Reply box :wink:)
kliker said:
I applied kirchhof's law and I have this:

36 - 5*I - I1*4 = 0
36 - 5*I + 20 - 2*I2 - 14 = 0
20 - 2*I2 - 14 + I1*4 = 0

The circuit only has two independent loops, so you can only get two independent equations from it.

The third Kirchhoff equation you need is for one of the junctions. :smile:
 
tiny-tim said:
Hi kliker! :smile:

(try using the X2 tag just above the Reply box :wink:)The circuit only has two independent loops, so you can only get two independent equations from it.

The third Kirchhoff equation you need is for one of the junctions. :smile:


hi, thanks for the answer

if we say I = I1 + I2 and take the first two equations

then we will have

36 -5*I1 - 5*I2 - 4*I1 = 0
36 - 5*I1 -5*I2 +20 - 2*I2 - 14 = 0

36 - 5*I2 - 9*I1 = 0
36 - 5*I1 - 7*I2 + 6 = 036 - 5*I2 - 9*I1 = 0
42 - 5*I1 - 7*I2 = 0

then by solving the equations I found the desired results

thanks a lot

Ps: what's the x2 tag? I can't find it
 
Hi kliker! :smile:

(just got up :zzz: …)
kliker said:
…then by solving the equations I found the desired results

:biggrin: Woohoo! :biggrin:
Ps: what's the x2 tag? I can't find it

Press the "QUOTE" button or the "Advanced Reply" button, and you get to the Reply to Thread page, with loads of useful tags to play with, above the box where you enter your text. :wink:
 
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