Solid Mechanics, calculating reaction forces and M(X) for a cantilever thing

AI Thread Summary
The discussion focuses on calculating reaction forces and moment (M(X)) for a cantilever beam. The user attempts to find the reaction force on the right side by setting the sum of moments on the left to zero, leading to the equation r_y = -M_0/L. There is uncertainty regarding the moment imparted by the wall and the boundary conditions, with the user suggesting v(0) = v(L) = 0. Clarifications are provided about the left support's capabilities, indicating that if it can resist moment, the assumption of r_y being zero is incorrect, potentially leading to a mechanism situation. The conversation emphasizes the importance of accurately interpreting support conditions in solid mechanics calculations.
PenTrik
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Homework Statement


ProblemCheck.jpg



Homework Equations


M = F * D


The Attempt at a Solution



For a, I need to find the reaction force on the right side. So what I first did was make the sum of the moment on the left equals zero.
0 = M_0 + r_y * L.
r_y = \frac{-M_0}{L}
I think this is right.

When you take net sum of the moments, then there should be no moment imparted by the wall correct? I'm not sure.

For my M(X) term, assuming that I have my reaction forces on the right correct, it should be
M_0 - \frac{M_0}{L} * (L-X)

As for the boundary conditions, I'm not really sure what they should be. I'm pretty sure they're supposed to mean v(0) = v(L) = 0

I'm not sure if this is correct at all.
 
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The support on the left is unusual, if not impractical, but I interpret it as being a normal encastre support resting rx and moment, but with no vertical restraint. Therefore ry must be zero. Your ry=M0/L is correct for a left hand support resisting ry but not rx. Are you sure the diagram is correct?
If the left support is capable of resisting moment then your assumption that it is zero is not correct. If the left support resists only rx, then the whole thing is a mechanism, with rotation about the right support.
 
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