Thermodynamics - Vapour Power Plants

AI Thread Summary
A compressor processes 4 kg/s of air, increasing its pressure from 1 bar to 4 bars and temperature from 25°C to 200°C. The power input to the compressor is calculated at 703.5 kW, with an isentropic efficiency of 0.83. The user successfully calculated the power input using the formula involving mass flow rate and specific heat capacity but struggled to determine the isentropic efficiency. To find the isentropic enthalpy change, it is recommended to reference a table of ideal gas properties for air. The discussion emphasizes the importance of accurate data for calculating thermodynamic properties in vapor power plant applications.
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Homework Statement


A compressor takes in 4 kg/s of air at atmospheric pressure and temperature, 1 bar and 25 degrees C. Air leaves the compressor at 4 bars and 200 degreesC. Calculate the power input to the compressor and its isentropic efficiency. For air Cp=1.005 and Cv=0.718 kJ/kg K

Answers: (703.5 kW, 0.83)

Homework Equations



(h2s - h1)/(h2-h1)

The Attempt at a Solution


I have already calculated the power input by using mass flow rate x Cp x delta T, however I am unable to find the isentropic efficiency. My attempt so far has been to divide Power input by mass flow rate to obtain h2-h1. The h2-h1 value i have obtained is 175.9kJ. I need help in finding h2s-h1.

I am doing this questions as exam preparation (this has nothing to do with coursework/homework) so maximum help would be very helpful.

Thanks
 
Physics news on Phys.org
Find a table of ideal gas properties for air that list T, h and Pr. Pr is the relative pressure for air when S2-S1=0 (constant entropy). Find h1, h2 and Pr1 from the table, h2s is tricky.

For the special case of air modeled as an ideal gas and S2-S1=0 this relation holds true:

P2/P1=Pr2/Pr1 solve for Pr2. Look up Pr2 in table and note corresponding h2s of about 443 Kj/Kg

From Fundamentals of Engineering Thermo. Moran and Shapiro edition 4, P. 276
 
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