- #1
EKL622
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Bill is farsighted and has a near point located 116 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm from her eyes. Both have glasses that correct their vision to a normal near point (25.0 cm from the eyes), and both wear glasses 2.0 cm from the eyes. Relative to the eyes, what is the closet object that can be seen clearly in the following situations.
1/f = 1/do + 1/di
P=1/f
I determined the powers (P) of the people's glasses using P= 1/do + 1/di where do was 0.25-0.02 and di was near point(in meters)+0.02. For Bill: P = 1/(0.23) + 1/-1.16+0.02 = 3.47 diopters. For Anne: P = 1/0.23 + 1/-0.72+0.02 = 2.96 diopters. I then switched the powers around, used the same di as before, and solved for do. I got 48cm for both of them, but this is wrong. Can anybody tell me what I am doing wrong? I am definitely a little confused about when you need to take the distance between the glasses and eye into account and whether you add or subtract it. Thanks!
1/f = 1/do + 1/di
P=1/f
I determined the powers (P) of the people's glasses using P= 1/do + 1/di where do was 0.25-0.02 and di was near point(in meters)+0.02. For Bill: P = 1/(0.23) + 1/-1.16+0.02 = 3.47 diopters. For Anne: P = 1/0.23 + 1/-0.72+0.02 = 2.96 diopters. I then switched the powers around, used the same di as before, and solved for do. I got 48cm for both of them, but this is wrong. Can anybody tell me what I am doing wrong? I am definitely a little confused about when you need to take the distance between the glasses and eye into account and whether you add or subtract it. Thanks!
