Mean Monthly Car Accidents: Analyzing Data from January to December

AI Thread Summary
The mean number of car accidents per month from January to September was 630, while from October to December it increased to 810. To find the overall mean for the year, the total number of accidents for the first nine months and the last three months was calculated. The total was found to be 675 accidents per month when averaged over the entire year. The solution was confirmed to be correct, highlighting the straightforward nature of the calculation. This analysis emphasizes the seasonal variation in car accidents throughout the year.
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Homework Statement



From January to September, the mean number of car accidents per month was 630. from Oct - Dec the mean was 810 accidents per month.

What was the mean number of car accidents per month for the whole year?



Homework Equations





The Attempt at a Solution



(630)(9) + (810)(3) = 675
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Thanks, it just seemed too simple!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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