Expected Monthly Profit for a Small Manufacturing Firm

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Homework Help Overview

The discussion revolves around calculating the expected monthly profit for a small manufacturing firm based on the number of machines sold, which follows a specific probability distribution. The profit function is defined in terms of the number of machines sold, and participants are exploring the expected value of this profit function.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to calculate the expected profit using the given probabilities and profit function. There is a discussion about the correct application of the expected value and the potential oversight of outcomes in the probability distribution. Some are questioning the addition of the mean of X to the expected profit calculation and are exploring the linearity of expectations.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on how to approach the problem. There is recognition of a possible missing outcome in the probability distribution, and some participants are exploring different interpretations of the calculations involved. No consensus has been reached on the correct method or final answer.

Contextual Notes

Participants are working within the constraints of the problem statement, which specifies the probabilities of selling 1 or 2 machines and indicates that no more than 2 machines are sold per month. There is also mention of an official answer that differs from some participants' calculations.

Of Mike and Men
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Homework Statement


A small manufacturing firm sells 1 machine per month with 0.3 probability; it sells 2 machines per month with 0.1 probability; it never sells more than 2 machines per month. If X represents the number of machines sold per month and the monthly profit is 2X2 + 3X + 1 (in thousands of dollars), find the expected monthly profit.

Homework Equations

The Attempt at a Solution


E(2X2 + 3X + 1) = ∑(2X2 + 3X + 1)f(x), x = 1, 2
= (2+3+1)(.3) + (8+6+1)(.1)
= 1.8 + 1.5
= 3.3
3.3 * 1000 = $3,300

The answer in the back is $3,800.

If I take my 3.3 and add the mean of E(X) = .3(1) + 2(.1) = 0.5, I get 3.8 * 1000 = $3,800. I'm not sure if this is coincidence or actually how you solve the problem. If it's how you solve the problem, I don't understand why you add the mean of X. If it's not the way you solve it, I'm not sure what to do and would like some hints (but not a solution -- if possible) as to where to go.

Thanks.
 
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You are missing one possible outcome ...

Edit: Not that that actually fixes the problem ...
 
Of Mike and Men said:

Homework Statement


A small manufacturing firm sells 1 machine per month with 0.3 probability; it sells 2 machines per month with 0.1 probability; it never sells more than 2 machines per month. If X represents the number of machines sold per month and the monthly profit is 2X2 + 3X + 1 (in thousands of dollars), find the expected monthly profit.

Homework Equations

The Attempt at a Solution


E(2X2 + 3X + 1) = ∑(2X2 + 3X + 1)f(x), x = 1, 2
...the mean of E(X) = .3(1) + 2(.1) = 0.5

So profit ##= 2X^2 + 3X + 1##

##E[profit] = E[2X^2 + 3X + 1] = E[2X^2] + E[3X] + E[1]##

by linearity of expectations.

This last line should be simplified a bit -- how would you do it? You correctly calculated ##E[X]##. What is ##E[X^2]##? Or if you prefer, what is the Variance -- you can recover ##E[X^2]## from that.
 
I'm getting an answer a touch higher than the 3.8 (thousand) mentioned as the official one, though.
 

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