How long does it take for a car to travel 1200 km at a speed of 50 mph?

AI Thread Summary
To determine how long it takes for a car traveling at 50 mph to cover a distance of 1200 km, first convert kilometers to miles, resulting in approximately 745.2 miles. Using the formula Distance = Speed × Time, the calculation becomes 745.2 miles divided by 50 mph. This results in a travel time of about 14.9 hours. Understanding unit conversion is crucial for solving this type of problem effectively.
roger
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Homework problem...

Please can you help me with this problem.
I don't understand what its asking and I don't know where to begin :

It says : A car travels at a speed of 50mph from point A to B.
The distance traveled is 1200 km. How long does the journey take ?


Thanks guys for any help !


Roger
 
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roger said:
It says : A car travels at a speed of 50mph from point A to B.
The distance traveled is 1200 km. How long does the journey take ?
They want you to find the travel time. Use Distance = Speed X Time. Beware of units.
 
roger said:
Please can you help me with this problem.
I don't understand what its asking and I don't know where to begin :

It says : A car travels at a speed of 50mph from point A to B.
The distance traveled is 1200 km. How long does the journey take ?


Thanks guys for any help !


Roger

1200 kilometers (km) × 0.621 = 745.2 miles (mi).
distance=rate*time (in same units)

\frac{745.2 miles}{50\frac{miles}{hour}} =
about 14.9 hours
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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