What is the max E that teh electron can obtain?

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The discussion centers on determining the maximum energy an electron can obtain after a photon with 20 keV scatters off it. The relevant equation involves the change in wavelength related to the scattering angle. Clarification is sought on how to approach the problem, particularly regarding the implications of different scattering angles (0, 90, and 180 degrees). The user expresses confusion about starting the calculations and understanding the physics behind the scattering process. Overall, the thread highlights the need for guidance in applying the Compton scattering formula to find the electron's maximum energy.
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A photon having 20 keV scatters from a free electron at rest. What is the maximum energy that the electron can obtain?

Homework Equations


\lambda' - \lambda = (h/mc)(1-cos(theta)

The Attempt at a Solution


i just don't know where to get started or anythign can someone show me how to do this?
 
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Do you know what happens when the scatter angle is 0 degrees, 90 egrees, and 180 degrees?
 
no that's why i don't get how to do this.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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