Potential Difference in a van der graaff generator

AI Thread Summary
The discussion revolves around calculating the highest potential difference in a van der Graaff generator, specifically between its high-voltage terminal and the surrounding pressure vessel. The problem states that the electric field in the gas must not exceed 1.6 x 10^7 volts/m, leading to a derived potential difference of 31.1 MV, with the intershield at 18.8 MV to prevent breakdown. Participants are attempting to solve the problem using the equation E = q/4πε₀r² and integrating to find the potential difference. There is confusion regarding the relationship between electric field strength and distance, particularly whether E varies as 1/r. The thread highlights the complexities of electromagnetism calculations and the importance of understanding electric field behavior.
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Hi, this problem is from 'Electromagnetism' by Grant & Phillips and it states,

Homework Statement


'http://i1129.photobucket.com/albums/m505/physicsbird1/126fig.png" shows a cross-section of the cylindrical high-voltage terminal of a van der Graaff generator, surrounded by an 'intershield' and a pressure vessel, both of which are also cylindrical. The gas in the pressure vessel breaks down in electric fields greater than 1.6 x 10^{7} volts/m. If the radii of the terminal, intershield and pressure vessel are 1.5 m, 2.5 m and 4 m respectively, what is the highest potential difference that can be maintained between the terminal and the pressure vessel?'

The answers given in the back of the book: '31.1 MV. When the terminal is at this voltage the intershield must be at 18.8MV to prevent breakdown.'


Homework Equations


d∅ = -E\bulletdr

E = q/4πε₀r^{2}

The Attempt at a Solution



1.6x10^{7} = q/4πε₀(2.5)^{2}

1.00x10^{8} = q/4πε₀ (Let q/4πε₀ = A)

A = 1.00x10^{8}


∅_{B} - ∅_{A} = -1.00x10^{8}\int^{4}_{1.5}(1/r^{2})

= -1.00x10^{8}[-1/r]^{4}_{1.5}<br /> <br /> = -1.00x10^{8} [-1/4 + 1/1.5]<br /> <br /> = -4.17x10^{7}<br /> <br /> So... can anybody tell me where I&#039;ve went wrong?
 
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You wrote, "E = q/4πε₀r^2"

E goes as 1/r ?
 
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