Schrodinger Equation: Particle in a Box

AI Thread Summary
In the discussion about the Schrödinger Equation for a particle in a one-dimensional infinite square well with an infinite potential step, participants clarify the potential energy configuration. The potential is defined as V(x) = 0 for the regions outside the step and V(x) = +infinity within the step, leading to the conclusion that the particle is confined to the left well. This configuration suggests that the particle is more likely to be found in the left well due to the infinite potential barrier preventing access to the right well. The energy levels in this modified system are expected to be higher than those in the original box without the infinite step. Overall, the introduction of the infinite potential step alters the spatial distribution and energy characteristics of the particle.
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Homework Statement



We have been examining a one-dimensional infinite square well where the infinite walls are located at -b and +b. The energy levels in this quantum system are non-degenerate, that is for each energy there is only one wave function. Let us place an infinite potential step between -b/2 and +b/2.
  • Is the particle more likely to be in the left or the right infinite square well?
  • What are the new energy levels and wave functions of this modified system?
  • Are the energy levels degenerate, and if so, what is the degeneracy?
  • Are the new energies higher or lower than the box without the infinite step?

Homework Equations



Time-independent Schrodinger Equation

The Attempt at a Solution



My main question involves how to interpret this problem. In my reading, the potential is just V(x) = 0 for -b < x < a and V(x) = +infinity for a < x < b where -b/2 < a < b/2. If my reading is correct, then wouldn't the particle only be in the left square well? (Since any particle would just be reflected from the region with infinite potential)

Thanks
 
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I read it the same way, all the step does is to reduce the width of the well.
 
I read it to mean that V(x)=0 for -b≤x≤-b/2 or b/2≤x≤b and V(x)=infinity everywhere else.
 
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