Sure, I would be happy to help you with your assignment on quantum physics and ionization energy. First, let's start with the concept of ionization energy. Ionization energy is the minimum amount of energy required to remove an electron from an atom or molecule. In the case of a hydrogen atom, the ionization energy is 13.6 electron volts (eV).
Now, let's address your first question about the absorption of light causing ionization. Yes, the absorption of light can cause ionization in a hydrogen atom. This is because when a photon of light is absorbed by the atom, it transfers its energy to the electron, giving it enough energy to overcome the attractive force of the nucleus and escape from the atom. However, not all frequencies of light will cause ionization. Only photons with energies equal to or greater than the ionization energy of the atom will be able to ionize it.
To determine if a light of frequency 7.00x10^15 Hz can cause ionization in a hydrogen atom, we can use the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.626x10^-34 J*s), and f is the frequency of the light. Plugging in the values, we get E = (6.626x10^-34 J*s)(7.00x10^15 Hz) = 4.64x10^-18 J. Converting this energy to electron volts, we get 4.64x10^-18 J / 1.6x10^-19 J/eV = 29 eV. Since this energy is greater than the ionization energy of hydrogen, which is 13.6 eV, it is possible for a photon with a frequency of 7.00x10^15 Hz to cause ionization in a hydrogen atom.
Moving on to your second question about calculating the wavelengths of the radiations in the Lyman series in the hydrogen spectrum. The Lyman series refers to the group of spectral lines in the hydrogen atom that are emitted when an electron transitions from a higher energy level to the first energy level (n = 1). The equation for calculating the wavelength of these spectral lines is given by the Rydberg formula: 1/λ = R(1/nf^2 - 1/ni^2), where λ is the wavelength, R is the Rydberg constant (1.097