When to use fourier integral instead of fourier series expansion

AI Thread Summary
Fourier integrals are used for non-periodic signals to obtain their amplitude spectrum, while Fourier series are applicable only to periodic functions. The Fourier integral can handle square integrable functions and can also represent periodic functions using the Dirac delta function. In contrast, Fourier series expansion is specifically designed for periodic functions. The key distinction lies in the nature of the signal: use Fourier series for periodic signals and Fourier integrals for non-periodic ones. Understanding when to apply each method is crucial for accurate signal analysis.
Naughty Boy
Messages
1
Reaction score
0
Suppose, I have a non-periodic signal for which amplitude spectrum is to be obtained . For this why should Fourier integral be used instead of Fourier series expansion . I want to know when to use Fourier inerals and when to use Fourier series . Please let me know all the details .
 
Physics news on Phys.org
If memory serves Fourier integral applies to square integrable functions and, with the use of Dirac delta function, to periodic functions like sine and cosine. The Fourier series expansion applies to periodic functions.
 
You use Fourier series if the function is periodic, transforms if it's not.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top