Accerleration from power, mass & speed

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To find the maximum acceleration of a 1200 kg car producing 50 kW of power at 60 mph, the relevant equations are P=Fv and F=ma. Converting 60 mph to meters per second gives approximately 26.6 m/s. Using the power equation, the maximum force can be calculated as P/v, leading to an acceleration of about 1.6 m/s². The conclusion is that the maximum acceleration of the car is 1.6 m/s².
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Homework Statement



A car of mass 1200 kg produces a maximum power of 50 kW. Find the maximum acceleration of the car when it is traveling at 60 mph.
(A). 1.6 m/s2. (B). 0.4 m/s2. (C). 0.7 m/s2. (D). 2 m/s2. (E). 3 m/s2

Homework Equations



P=Fv
F=ma
mph-m/s = (miles x 1.6 x 1000)/3600

The Attempt at a Solution



P=Fv
P=mav
P/mv=a

m/s= (60 x 1.6 x 1000)/ 3600

50000/1200x26.6 = 1.56...
So I'm saying that the anser is 1.6

i think i have done this right however as i no longer have access to the answers i can't tell. If any thing is wrong could you just point me to the area (i.e. equations or numbers)
 
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KESTRELx said:

Homework Statement



A car of mass 1200 kg produces a maximum power of 50 kW. Find the maximum acceleration of the car when it is traveling at 60 mph.
(A). 1.6 m/s2. (B). 0.4 m/s2. (C). 0.7 m/s2. (D). 2 m/s2. (E). 3 m/s2

Homework Equations



P=Fv
F=ma
mph-m/s = (miles x 1.6 x 1000)/3600

The Attempt at a Solution



P=Fv
P=mav
P/mv=a

m/s= (60 x 1.6 x 1000)/ 3600

50000/1200x26.6 = 1.56...
So I'm saying that the anser is 1.6

i think i have done this right however as i no longer have access to the answers i can't tell. If any thing is wrong could you just point me to the area (i.e. equations or numbers)

Your answer is fine.
 
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