How fast can a hoist lift a 326 kg load with 12.6 kw of power?

  • Thread starter Thread starter DethRose
  • Start date Start date
  • Tags Tags
    Power Work
AI Thread Summary
A hoist rated at 12.6 kW can lift a 326 kg load at a speed of approximately 3.94 meters per second. This calculation is based on the power-to-force relationship, where power is equal to force multiplied by speed. The force exerted by the load due to gravity is approximately 3197 N. The confusion about units arose from mixing hours and seconds in the calculations. Ultimately, the correct interpretation of the power and force leads to the conclusion that the hoist operates at 3.94 m/s.
DethRose
Messages
101
Reaction score
0
I have a work and power problem but I am not sure what it has to do with the work and power formulas and have no idea how to solve it.

The question is

with what speed can a lifting hoist rated at 12.6 kw raise a 326 kg load?

i found distance to be 9401.94 but that's as far as i got

help please

thanks
 
Physics news on Phys.org
You found the "distance to be 9401.94"? What distance??

12.6 kw is 12600 Joules per hour. In One Hour, it does 12600 Joules of work which corresponds to ( since w= mgh, (326)(9.81)h= 12600 ) 3.94 meters. It can only lift the 326 kg load at 3.94 meters per hour!
 
Did you try using

P = Fv
W = Fx

Because those two formula would give you the answer for velocity/speed by rearranging the variables around.
 
HallsofIvy said:
You found the "distance to be 9401.94"? What distance??

12.6 kw is 12600 Joules per hour. In One Hour, it does 12600 Joules of work which corresponds to ( since w= mgh, (326)(9.81)h= 12600 ) 3.94 meters. It can only lift the 326 kg load at 3.94 meters per hour!

What hour...? :confused: U mean second... :wink: GDit.It gives the power:the power is force times speed.
The power is 12.6 KW=12600W.The force is nothing but the gravity:
F=mg=326kg*9.80665ms^(-2)=3196,9353N approx=3197N
Speed is power over force:
v approx=12600W/3197N approx=3.94 m/s.That is METERS PER SECOND... :wink:

Daniel.

EDIT:The natural multiples of ten are usually noted by capital letters.
10^{3}\rightarrow K apud "Kilo".Kg,Km,KW,KJ,KN,...
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top