How Much Power Is Dissipated in Each Resistor in a Multiloop Circuit?

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In a multiloop circuit with resistors R1 (32 Ω), R2 (45 Ω), and R3 (60 Ω), the power dissipated in each resistor can be determined using loop and junction laws. The discussion clarifies that the direction of traversal in applying loop law does not need to be consistent across different loops; respecting potential drops and rises is sufficient. If the direction is reversed in one loop, the equations will simply be multiplied by -1. It is suggested to analyze the outer loop for simplicity, reducing the chance of errors. The participant successfully solved the problem after this clarification.
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Homework Statement


26-p-063-alt.gif


Three resistors, R1 = 32 Ω, R2 = 45 Ω, and R3 = 60 Ω, are connected in a multiloop circuit, as shown in the figure. Determine the amount of power dissipated in the three resistors.

Homework Equations



loop law
junction law

The Attempt at a Solution



(1) i1 +i2 +i3 = 0

(2) 9 - 45 i2 + 32 i1 = 0

(3) 15 +60 i3 + 9 - 45 i2 = 0

when you use the loop law, don't you have to go the same direction with every loop?
In the equation (3) it is going clockwise, and in equation (2) it is going counter-clockwise.
Is this wrong?
 
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You don't have to go the same direction with every loop. All you have to do is respect the potential drops/rises as specified by the chosen current directions (as indicated by the arrows) as you traverse the components during your "tour" around the loop.
 
Hi Cisneros778! :smile:
Cisneros778 said:
when you use the loop law, don't you have to go the same direction with every loop?
In the equation (3) it is going clockwise, and in equation (2) it is going counter-clockwise.
Is this wrong?

No, it doesn't matter which way round you go …

if you went the other way round one loop, everything would be multiplied by -1, wouldn't it? :wink:

btw, it might be easier to take the outside loop rather than the bottom loop (the outside loop is the sum of the other two), since it has one less term in it (and one less chance of making a mistake! :biggrin:)​
 
Thank you so much. I got the answers correct!
 
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