Understanding Symbolic Math in MATLAB: Real and Imaginary Parts

AI Thread Summary
In MATLAB, when using symbolic math, the imaginary unit is represented as 'sqrt(-1)' instead of 'i' in expressions. This occurs because MATLAB defaults to using 'sqrt(-1)' for clarity in symbolic computations. To extract the real part of an expression, the command 'real(ans)' returns the expression with 'sqrt(-1)' still present, indicating that the output retains the symbolic form. Users seeking to simplify the expression or convert it to a numerical form may need to apply additional functions or methods. Understanding these nuances is crucial for effective symbolic math manipulation in MATLAB.
zhaniko93
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I have such MATLAB problem: I create variables R1 RF R2 and w so:
Code: 
syms RF R1 R2 w
then I write expression:
Code: 
3*R1*w*(RF + 200)/((R2*w*29*i + 3)*(3*R1*w - 2*i))
which gives:
Code: 
(3*R1*w*(RF + 200))/((3*R1*w - 2*sqrt(-1))*(R2*w*29*sqrt(-1) + 3))
why sqrt(-1) and not i? furthermore? if I want real part of the expression and write:
Code: 
real(ans)
it gives:
Code: 
3*real((R1*w*(RF + 200))/((3*R1*w - 2*sqrt(-1))*(R2*w*29*sqrt(-1) + 3)))
can anyone please help me??
 
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