Small but pressing Fourier series question

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SUMMARY

The discussion focuses on a Fourier series problem involving the calculation of coefficients using the formula ck = 1/T ∫ a-a x(t)e-jk2pit/T. The user initially miscalculated the pulse height, assuming it to be 1 instead of the correct value of 1/2a. This adjustment leads to the correct formulation of the Fourier series, which is x(t) = Ʃk=-∞∞ (sin(k.a.2pi/T).a-a e-jk2pit/T)/k.pi.2.a. The user also references a related problem for further assistance.

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toneboy1
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Homework Statement


Please see picture attached


Homework Equations





The Attempt at a Solution


ck = 1/T ∫ a-a x(t).e-jk2pit/T

So x(t) = Ʃk=-∞ (sin(k.a.2pi/T).a-a e-jk2pit/T)/k.pi

but is is supposed to be:

So x(t) = Ʃk=-∞ (sin(k.a.2pi/T).a-a e-jk2pit/T)/k.pi.2.a

but I don't know why?

Thanks
 

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