Del operator crossed with a scalar times a vector proof

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"Del" operator crossed with a scalar times a vector proof

Homework Statement


Prove the following identity (we use the summation convention notation)

\bigtriangledown\times(\phi\vec{V})=(\phi \bigtriangledown)\times\vec{V}-\vec{V}\times(\bigtriangledown)\phi

Homework Equations



equation for del, the gradient, curl..

The Attempt at a Solution



im kind of confused on the first step...I broke it down into the following; however, levi civita symbols aren't my cup of tea and I get pretty confused about it...anyway here's what I did:

\bigtriangledown\times(\phi\vec{V})=(\epsilon_{ijk})\partial_i\vec{V}\phi\hat{x}_k

I don't know if this first step is right or if I decomposed the cross product right ?
 
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You should have the j:th component of V in your expression,
\nabla \times (\phi \vec{V}) = \epsilon_{ijk} \partial_i (\phi V_j) \hat{x}_k
 


The form you've written is completely equal to the one seen in math/physics books

\nabla\times \left(\phi\vec{V}\right) = \nabla\phi\times\vec{V} + \phi\nabla\times\vec{V}
 


Thanks for the replies, I'm just not sure what to do after what clamtrox said to do, the whole proofing business if pretty new to me :/
 


You need two more steps. Apply the product rule for differentiation and then once you obtain a sum of two terms, reconstruct vectors from their components.
 
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