Electric Field of a Spherical Insulator

AI Thread Summary
To find the electric field of a spherical insulator with a charge density of ρ = ρo/r², one must integrate the charge density over the volume enclosed by a Gaussian surface. The charge density varies with distance, but remains constant in thin shells, allowing for straightforward volume calculations. For a Gaussian surface inside the sphere, integrate from 0 to r', while for outside, integrate from 0 to R. The resulting electric field can then be derived using the equation EA = Qencl/εo. Understanding the integration process is crucial for solving the problem effectively.
Stealth849
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Homework Statement



A spherical insulator of radius R and charge density ρ = ρo/r2 where r is the distance from its centre. Find the electric field at a point inside and outside the insulator.


Homework Equations



EA = Qenclo

The Attempt at a Solution



What's throwing me off is the charge density. Setting up a gaussian sphere, I don't know what to do to find Q for the formula.
 
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You need to integrate he charge density enclosed in the Gaussian surface.

ehild
 
Can you elaborate a little bit?

I'm not too sure what I should be integrating here...

ρ should be in C/m3

To get Q from ρ, I need to cancel the volume... I don't see what to integrate to achieve this though.

Thanks
 
Charge density is the charge of unit volume. If it is constant you get the charge by simply multiplying the volume with the density.
The density varies with the distance from the centre here. But it is constant in a very thin shell.
What is the volume of a shell if its radius is r and thickness Δr?

ehild
 
hm,

if i integrate surface area from 0 ro the Radius, that would give me volume..

so if I take the integral of ρ*dA from 0 to R

where dA = 4*pi*r^2*dr ?
 
Yes, that will be the whole charge of the sphere. Calculate the field from it outside the charged sphere.
If the Gaussian surface is inside the charged sphere at distance r' < R from the centre, you need to integrate from 0 to r'.

ehild
 
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