How do I Expand a Cubic Problem?

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To expand a cubic equation, first handle the operations within the brackets, then simplify by combining like terms. The constant term, such as +2, should be added after completing the cubic expansion. An example provided illustrates how to expand and simplify expressions correctly. The final solution can often be further simplified by combining coefficients of like terms. Understanding these steps is crucial for accurately solving the problem.
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Homework Statement



Hey

I have a question that I have to do that involves expanding a cubic. It is given in the form y = , once it is found I have to square it and then substitute it into a formula to find the area. All I need help with is the expansion than after that it's quite easy.

Homework Equations



Sorry I don't know how to use the options here to create formulas etc. But I hope the following link works.

https://www.physicsforums.com/attachment.php?attachmentid=58828&stc=1&d=1368927170

This is the equation that I need to expand.

The Attempt at a Solution



I know how to expand a cubic already, it's not that difficult. The problem is with the +2 at the end of the equation. Do I ignore it, expand the brackets and add it on at the end?
 

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Hi Grove1996,

Usually you would do the operations in the brackets first and then simplify after. So yes you would need to add the 2 to the constant from the cubic expansion

So when do any expansion, you would sum up all the x's and constants and so on.

e.g. (x+1)2+4 = (x+1)(x+1) + 4 = x2 + x +x +1 +4 = x2 + 2x + 5
 
rock.freak667 said:
Hi Grove1996,

Usually you would do the operations in the brackets first and then simplify after. So yes you would need to add the 2 to the constant from the cubic expansion

So when do any expansion, you would sum up all the x's and constants and so on.

e.g. (x+1)2+4 = (x+1)(x+1) + 4 = x2 + x +x +1 +4 = x2 + 2x + 5

Thank you :)
 
Yes, it is correct, but you can further simplify it:

For example:
## -1.5 x^4 -3 x^4 = (-1.5 - 3)x^4 = -4.5x^4 ##
 
Cogswell said:
Yes, it is correct, but you can further simplify it:
In other words: Combine like terms.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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