Collision of multiple particles

AI Thread Summary
The discussion revolves around solving a collision problem involving multiple particles, where the original poster believes the answer should be e = 1, while the provided answer is 2/3. Respondents indicate that the method used by the poster is suitable only for two-particle collisions and suggest necessary adjustments for multiple particles. There is a consensus on the need to conserve momentum for the entire system, which may involve considering multiple lines of impact. Further adjustments and calculations are recommended to arrive at the correct solution.
coldblood
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Hi friends,
I have an issue in solving a Collision of multiple particles.
Please Help me in solving this.
Thank you all in advance.

The problem is as:

https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-frc3/q71/s720x720/1395304_1432383000322139_406785433_n.jpg


Attempt:

https://fbcdn-sphotos-f-a.akamaihd.net/hphotos-ak-prn2/q81/s720x720/1380665_1432380623655710_1216390070_n.jpg

Friends according to me the answer should be e = 1, which is not any option and question says answer is 2/3 which is Option (a). Please try to help me in this.
I will appreciate the help.
 
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coldblood said:
Hi friends,
I have an issue in solving a Collision of multiple particles.
Please Help me in solving this.
Thank you all in advance.

The problem is as:

https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-frc3/q71/s720x720/1395304_1432383000322139_406785433_n.jpg


Attempt:

https://fbcdn-sphotos-f-a.akamaihd.net/hphotos-ak-prn2/q81/s720x720/1380665_1432380623655710_1216390070_n.jpg

Friends according to me the answer should be e = 1, which is not any option and question says answer is 2/3 which is Option (a). Please try to help me in this.
I will appreciate the help.
The method you applied is applicable for two particle collision only. You'll need to do adjustments before applying this method.
 
NihalSh said:
The method you applied is applicable for two particle collision only. You'll need to do adjustments before applying this method.

Well if I'll conserve momentum for the whole system there would be two lines of imapact.
Ok first I'll do some adjustment in that and then will continue.
 

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