Object at focal point of converging lense

[admajoremdeigloriam]

I have a simple question that I can't seem to answer...

why is it that when an object is at the focal point of a converging lense, the image is at infinity? How can you show this through ray diagrams?

 

[Andrew Mason]

I have a simple question that I can't seem to answer...

why is it that when an object is at the focal point of a converging lense, the image is at infinity? How can you show this through ray diagrams?

The lens equation:

\frac{1}{f} = \frac{1}{i} + \frac{1}{o}

What is the object distance if i = f? Or, what is the image distance if o = infinity?

AM

 

[thepatientmental]

When an object is placed at the focal point of a converging lens, the rays of light coming from that object will be parallel to the principal axis of the lens. This means that the refracted rays will also be parallel to the principal axis, and will not converge or diverge. As a result, the image formed by these refracted rays will appear to be at an infinite distance, or at infinity.

To demonstrate this through ray diagrams, we can draw three rays of light coming from the object towards the lens. The first ray will be drawn parallel to the principal axis and will pass through the focal point of the lens. The second ray will pass through the center of the lens and will not be refracted. The third ray will pass through the focal point on the other side of the lens and will emerge parallel to the principal axis.

These three rays will converge at a point on the other side of the lens, forming the image of the object. However, since the refracted rays are parallel to the principal axis, they will never actually meet at a point, giving the illusion that the image is at an infinite distance.

In summary, when an object is placed at the focal point of a converging lens, the refracted rays will be parallel to the principal axis, resulting in an image at infinity. This can be shown through ray diagrams by drawing three rays and observing how they behave after passing through the lens.