Solve] Time to Boil 1.1 kg Water with 1500 W

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    Thermodynamics
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To determine the time required to boil away 1.1 kg of water using a 1500 W stove burner, the latent heat of water must be considered. The relevant equation for heat transfer is q = mct, where 'm' is mass, 'c' is specific heat, and 't' is time. After reaching the boiling point, the energy needed to convert the water to steam can be calculated using the latent heat of vaporization. The relationship between power, energy, and time will then provide the final time needed for the process. This approach ensures an accurate calculation of the boiling time.
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Homework Statement


A stove burner supplies heat to a pan at the rate of 1500 W. How
long will it take to boil away 1.1 kg of water, once the water
reaches its boiling point?


Homework Equations


q = mct


The Attempt at a Solution



heat transfer = 1500 W, m = 1.1 KG Tf = 100
[
 
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Look up latent "heat of water". That will allow you to calculate the amount of energy needed to turn 1.1kg of water at 100C into steam at 100C.

Then remember the equation that relates Power, Energy and Time.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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