Contravariant and covariant indices

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The discussion focuses on the notation of contravariant and covariant indices in the context of Lorentz transformations. It clarifies that the placement of indices, whether stacked or side by side, can affect interpretation but may not change the underlying mathematics if conventions are consistently applied. The relationship between the Lorentz transformation and its inverse is explored, highlighting that the notation can lead to different expressions depending on how indices are raised or lowered. It emphasizes that using standard conventions is crucial for clarity and correctness in tensor notation. Ultimately, while flexibility in notation exists, adhering to established conventions is recommended for consistency in mathematical communication.
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When we write contravariant and covariant indices, for example for the Lorentz transformation, does it matter if we write \Lambda^\mu\,_\nu or \Lambda^\mu_\nu?
i.e. if the \nu index is to the right of the \mu or they are at the same place with respect to left-right?
 
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Lorentz transformations are linear operators on ##\mathbb R^4## (or ##\mathbb R^2## or ##\mathbb R^3##). So they can be represented by matrices. (See the https://www.physicsforums.com/showthread.php?t=694922 about matrix representations of linear transformations). I will not make any notational distinction between a linear operator and its matrix representation with respect to the standard basis.

Let ##\Lambda## be an arbitrary Lorentz transformation. By definition of Lorentz transformation, we have ##\Lambda^T\eta\Lambda=\eta##. This implies that ##\Lambda^{-1}=\eta^{-1}\Lambda^T\eta##. Let's use the notational convention that for all matrices X, we denote the entry on row ##\mu##, column ##\nu## by ##X^\mu{}_\nu##. If we use this convention, the definition of matrix multiplication, our formula for ##\Lambda^{-1}## and the convention that every index that appears twice is summed over, we get
$$(\Lambda^{-1})^\mu{}_\nu = (\eta^{-1})^\mu{}_\rho (\Lambda^T)^\rho{}_\sigma \eta^\sigma{}_\nu = (\eta^{-1})^\mu{}_\rho \Lambda^\sigma{}_\rho \eta^\sigma{}_\nu.$$ This is where things get funny. It's conventional to write ##\eta_{\mu\nu}## instead of ##\eta^\mu{}_\nu##, and ##\eta^{\mu\nu}## instead of ##(\eta^{-1})^\mu{}_\nu##. If we use this convention, we have
$$(\Lambda^{-1})^\mu{}_\nu = \eta^{\mu\rho} \Lambda^\sigma{}_\rho \eta_{\sigma\nu}.$$ Now if we also use the convention that ##\eta^{\mu\nu}## raises indices and ##\eta_{\mu\nu}## lowers them, we end up with
$$(\Lambda^{-1})^\mu{}_\nu = \Lambda_\nu{}^\mu.$$ So if ##\Lambda## isn't the identity transformation, we have
$$\Lambda_\nu{}^\mu = (\Lambda^{-1})^\mu{}_\nu \neq \Lambda^\mu{}_\nu.$$ As you can see, the inequality is a result of the definitions of ##\eta_{\mu\nu}## and ##\eta^{\mu\nu}##, so if you use a notational convention that denotes these things by something else, or doesn't use these things to raise and lower indices, it may be OK to write ##\Lambda^\mu_\nu##.
 
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