Finding Effective Capacitance in a Circuit | Voltage Across Capacitor

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The discussion revolves around calculating the effective capacitance in a circuit using the formula (1/c1 + 1/c2)^-1. A participant questions why the effective capacitance must be multiplied by 2 instead of using the formula directly, which is already intended to yield effective capacitance. The conversation highlights the importance of understanding the relationship between charge and voltage across capacitors after reconnection, suggesting a method involving three equations to clarify the calculations. Additionally, it is noted that the multiple-choice answers provided contain incorrect units, indicating a potential shortcut to the correct solution. Overall, the focus is on ensuring clarity in calculations and understanding the principles behind effective capacitance.
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Homework Statement


here's my question and the working in the same photo.. my question is to find to find the effective capacitance in the circuit i use (1/c1 +1/c2)^-1 , why should can't just take effective c =
(1/c1 +1/c2)^-1 but must times 2 ? since (1/c1 +1/c2)^-1 is already effective capacitance. please ignore the irrelevant part . sorry for the messy work

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Why should effective capacitance be the criterion for obtaining the resultant voltage across the capacitors?

One way:
You can write 3 equations in 3 unknowns: Qb, Q1 and Q2 where
Qb is the charge on each plate before reconnection,
Q1 is the charge on plate 1 after reconnection
Q2 is the charge on plate 2 after reconnection

Then V after reconnection is obvious.
 
Last edited:
Can you explain what you calculated? It is hard to understand that with those unexplained formulas.

By the way, as this is a multiple choice question, there is a shorter way to find the right answer: three out of four answers do not have the correct units.
 
mfb said:
Can you explain what you calculated? It is hard to understand that with those unexplained formulas.

By the way, as this is a multiple choice question, there is a shorter way to find the right answer: three out of four answers do not have the correct units.

Ho ho, good point! Lousy choices!
 
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