Solving Problems Involving Tension & Weight

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The discussion focuses on solving a physics problem involving tension and weight of a picture hanging on a nail. The tension in each string segment is 3.5 N, forming a 45-degree angle. The user correctly sets up the equilibrium equation, concluding that the weight of the picture is 4.9 N. Participants confirm that the upward reaction force at the nail equals the weight of the picture. The importance of a free body diagram is emphasized for clarity in visualizing the forces involved.
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I looked in the physics book and couldn't find any similar examples. Maybe someone can tell me how to go about this problem:

A picture it hanging on a nail. The tension in each string segment which is holding up the picture is 3.5 N. The string forms a 45 degree angle on the two top corners of the picture frame.

a) What is the equilibrant or the upward reaction force of the nail?
b) What is the weight of the picture?

This is how I started going about it:
T1 + T2 + W = 0
Tsin45 + Tsin 45 - W = 0
2Tsin45 = W
2(3.5)sin45 = W = 4.9 N

Any pointers?
Thanks
 
Last edited:
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Is it 40° or 45°?
 
oops. typo- it's 45 degrees.
 
What does your free body diagram look like? Since the nail is the only item that is holding the picture up, you are correct with saying that the weight of the picture and the reaction force at the nail are equivilent.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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