Maximizing Golf Ball Distance and Hole in One: Intro Physics HW Help

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Homework Help Overview

The discussion revolves around a physics problem related to projectile motion, specifically focusing on maximizing the distance a golf ball can travel when struck by a golfer. The problem involves determining the time the ball spends in the air and the longest possible distance for a hole in one, assuming no rolling upon landing.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the optimal launch angle for maximizing distance, with some suggesting 45 degrees as the ideal angle. Various equations of motion are referenced, and there are hints about deriving relationships between variables. Questions about the effects of velocity on time and distance are raised.

Discussion Status

Several participants have contributed thoughts on the equations relevant to the problem, with some providing hints and insights into the relationships between the variables involved. There is an ongoing exploration of different approaches to the problem, but no consensus has been reached on a complete solution.

Contextual Notes

Participants are operating under the constraints of a homework assignment, which may limit the depth of their discussions and the completeness of their solutions. There is an emphasis on understanding the physics concepts rather than simply providing answers.

lolo
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hey everyone, i have a few questions that i just don't understand.
1) a golfer imparts a speed of 27.0m/s to a ball, it travels the max possible distance b4 landing on the green. the tee and the green are at the same level. a) how much time does the ball spend in the air? b) wat is the longest "hole in one" that the golfer can make, if the ball does not roll when it hits the ground?


i would really really appreciate ur help and if someone can do these problems can u please give clear solutions?
thanx a lot
 
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I believe 45 degrees is the angle that produces the longest distance in projectile motion.
 
a)
y = y_0 + v_{0y}t + \frac{1}{2}a_yt^2
x = x_0 + v_{0x}t + \frac{1}{2}a_xt^2
Both equations (especially the latter) reduce quite nicely with some logical thinking (what sort of velocity has an effect on the time?). Then just put the equations together and find the maximum (hint: derivate). Quickly done: 45 degrees does look like the correct answer. Now just throw the angle into the (reduced) equation you got in the first step.
Hint: Express v_0 in v_{0y} and v_{0x}

b) You already got the equation you need in a). Now just throw the velocity in and you're done.
 
Last edited:
Päällikkö said:
a)
y = y_0 + v_{0y}t + \frac{1}{2}a_yt^2
x = x_0 + v_{0x}t + \frac{1}{2}a_xt^2
Both equations (especially the latter) reduce quite nicely with some logical thinking (what sort of velocity has an effect on the time?). Then just put the equations together and find the maximum (hint: derivate). Quickly done: 45 degrees does look like the correct answer. Now just throw the angle into the (reduced) equation you got in the first step.
Hint: Express v_0 in v_{0y} and v_{0x}

b) You already got the equation you need in a). Now just throw the velocity in and you're done.

thanks that also just helped me
 
but i simply used the equation for range to find longest
distance which is same as X, R=X= Vox*T,
 

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