How Do You Determine U(x) for a Particle Under a Nonlinear Force?

  • Thread starter Thread starter eku_girl83
  • Start date Start date
  • Tags Tags
    Force
eku_girl83
Messages
89
Reaction score
0
A particle is under the influece of a force F=-kx+kx^3/(a^2), where k and a are constants and k is positive. Determine U(x) and discuss the motion. What happens when E=1/4 (k a^2)?

I know F = - grad U, but how do I use this fact to set up the problem?
Can someone help me to get started?

Thanks!
 
Physics news on Phys.org
This is a one-dimensional problem, so no need for gradients. Just F=-dU/dx

So start by finding (a) U(x).
 
eku_girl83 said:
A particle is under the influece of a force F=-kx+kx^3/(a^2), where k and a are constants and k is positive. Determine U(x) and discuss the motion. What happens when E=1/4 (k a^2)?
I know F = - grad U
In one-dimension, that's F(x) = -dU(x)/dx. Now what can you do to express U(x) in terms of F(x) ?

Edit : Started before Galileo's post was up...now redundant as it's saying the same thing.
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top