Figure:
My attempt at a Solution:
$$\overrightarrow{TFD}=TFD\dfrac{(-0,16\widehat{i}+0,11\widehat{j}-0,08\widehat{k})}{0,21}$$
View from above:
We calculate ##D##:
$$\sigma =90-\arctan \left( \dfrac{0,07}{0,240}\right)=73,74\, \textrm{º}$$
$$d=0,16\cdot \sin (\sigma)=0,1536\, \textrm{m}$$...