Calculating Electron Motion in an AM Radio Broadcasting Circuit

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The discussion focuses on calculating the motion of electrons in an AM radio broadcasting circuit operating at 550 kHz. For part (a), the time for electrons to complete one full cycle is determined as the reciprocal of the frequency, yielding approximately 1.818 microseconds. In part (b), the average speed of the electrons is given as 100 micrometers per second, and the hint suggests that the full range of motion occurs in half of the cycle. The user attempts to calculate the range by multiplying the speed by half the period but encounters an error in converting the result to nanometers. Clarification is sought on the correct approach to the calculations.
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Homework Statement


Consider the broadcasting circuit for an AM radio station which broadcasts at a frequency of 550 kHz. The electrons in such a circuit are moving back and forth in simple harmonic motion.

(a) How long does it take for the free electrons in this circuit to go back and forth once? Give your answer in μs.


(b) Assuming the average speed of the electrons is 100 μm/s, what is the range of motion of the electrons as they go back and forth in the wires of the circuit. (HINT: As the electron goes back and forth, it travels its full range every half cycle.) Give your answer in nm.
nm



Homework Equations


T=s/cycles
d=vt?


The Attempt at a Solution



the answer to a was easy - just the reciprocal of 550khz.

b, seems a little more confusing. I know the speed (100x10^-6) of the electrons, and the time (answer a), but my confusion is in the "hint". Would I multiply the time by 2?

Thank you!
 
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The hint is telling you that the electrons are traveling the full range of motion in 1/2 of a period.
 
Ok, so I multiplied v(100x10^-6) by (1/2)(1.818x10^-6) and got 9.09x10^-11. It asks for the answer in nm (^-9), so I entered 90.9, and it was incorrect. Can someone tell me what I am doing wrong? I only have 1 attempt left.
 
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