2 equal masses raised on pulley at constant velocity, what is the force ?

AI Thread Summary
Two equal masses are raised on a pulley at constant velocity, with one mass moving twice as fast as the other. The force acting on each mass is equal to its weight (mg), but the differing velocities suggest a misunderstanding of pulley mechanics. A net zero force is required for constant speed, allowing equal forces to produce different speeds based on time and applied force. The discussion highlights the importance of recognizing that pulleys can facilitate varying speeds without additional forces acting on the masses. Ultimately, the confusion stemmed from the relationship between force, speed, and the mechanics of the pulley system.
mldavis086
Messages
10
Reaction score
0

Homework Statement



2 equal masses (massA, massB) are raised up a pulley, at a constant velocity. massB has a velocity twice as fast as massA. What is the force acting on these 2 masses?

Homework Equations





The Attempt at a Solution



If it is a constant velocity, the upwards force must be equal to mg correct? So Fa=mg, Fb=mg. But if this is the case, how is it possible massB moves twice as fast as massA without an additional force acting on it?

I am confused, can anyone out there help me please?
 
Physics news on Phys.org
Hint: what do pulleys do? What are they for?

Note: a net zero force is needed to move at any constant speed - so two equal masses can have the same applied force and yet move at different constant speeds. You get different speeds by applying, for eg., the same unbalanced force for different amounts of time. But I don't think they are talking about the force on the mass - but the force applied to the end of the rope.

(However: I don't think all that is all the information you are given.)
 
No it is not all the given info. It was a power question but I got it figured out. I was just confused about the part where it could be any speed. But now it seems like a silly question now that I understand. Thanks though!
 
Once you understand something, earlier confusion often appears silly.
We are all wise in hindsight ;)
Cheers.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top