2 parallel rays are travelling in a medium

AI Thread Summary
Two parallel rays travel in a medium with a refractive index of 4/3, with one ray passing through a glass slab of thickness t and refractive index 3/2. The path difference between the two rays is determined by calculating their respective optical paths. The first ray's optical path is (4/3)t, while the second ray's optical path through the glass slab is (3/2)t. The correct path difference is found to be (1/8)t after considering the refractive index of the surrounding medium. The discussion emphasizes the importance of accurately accounting for the refractive indices when calculating optical paths.
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Homework Statement


2 parallel rays are traveling in a medium of refractive index 4/3. One of the rays passes through a parallel glass slab of thickness t and refractive index 3/2. What will be the path differnce between the two rays due to the glass slab?


The Attempt at a Solution



The optical path covered by the ray inside the glass slab equals the phase difference.
So x=3/2 x t

The answer is incorrect.
 
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Dear AbdulKadir, that is easy;
l=nx right?
for first one l=(4/3)t
for second one l'=(3/2)t
path difference is (1/6)t, don't get confused, other is not traveling at space it also in a medium
 


Phase difference would be the difference in optical paths. One ray goes through a medium of r index 3/2, other through 4/3. Find the optical paths and subtract.
 


sigmaro said:
AbdulKadir

:rolleyes:

sigmaro said:
l=nx right?
for first one l=(4/3)t
for second one l'=(3/2)t
path difference is (1/6)t, don't get confused, other is not traveling at space it also in a medium

The first ray doesnot travel through the glass slab. How did you write 4/3t?

Sourabh N said:
Phase difference would be the difference in optical paths. One ray goes through a medium of r index 3/2, other through 4/3. Find the optical paths and subtract.

So do you mean the answer will be (1/6)t?
 


Yes.
 


Sorry that answer is incorrect.
 


A trivial problem - We have assumed c = 1. Does the answer assume that too?

A not so trivial problem - The refractive index of glass slab wrt the surrounding medium is (3/2) / (4/3) = 9/8. So the path difference would be 9/8 * t - t = 1/8 * t. This makes more sense to me because the background medium is not air (with r index 1), but a medium with r index 4/3. Does it make sense to you?
 


You are correct now.
But I didnot understand one thing, why did you subtract t from 9/8*t ?
 


9/8 * t is the optical path through the glass slab (placed in water), t is the optical path in water. Path difference = Subtract them.

In other words, the same reason we subtracted 4/3 * t earlier.
 
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Thanks!
 
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